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Complex Number

Properties of Addition of Complex Numbers

Basic Operation Properties

Addition and scalar multiplication operations on complex numbers have interesting properties, similar to those of real numbers. These properties help us in performing calculations.

Let z1z_1, z2z_2, and z3z_3 be any complex numbers, and let cc and dd be any scalars (real numbers).

Commutativity

The order of addition does not matter; the result remains the same.

z1+z2=z2+z1z_1 + z_2 = z_2 + z_1

Example: (2+i)+(13i)=(13i)+(2+i)=32i(2+i) + (1-3i) = (1-3i) + (2+i) = 3-2i

Associativity

When adding three complex numbers, the grouping of the addition does not affect the result.

(z1+z2)+z3=z1+(z2+z3)(z_1 + z_2) + z_3 = z_1 + (z_2 + z_3)

Additive Identity (Zero Element)

There exists a complex number 0=0+0i0 = 0 + 0i (zero) such that when added to any complex number z1z_1, the result is z1z_1 itself.

z1+0=z1z_1 + 0 = z_1

Additive Inverse (Opposite)

Every complex number z1=x+iyz_1 = x + iy has an additive inverse (opposite), denoted by z1=xiy-z_1 = -x - iy, such that their sum is the zero element (0).

z1+(z1)=0z_1 + (-z_1) = 0

Example:

If z1=52iz_1 = 5-2i, then z1=5+2i-z_1 = -5+2i.

Then (52i)+(5+2i)=(55)+i(2+2)=0+0i=0(5-2i) + (-5+2i) = (5-5) + i(-2+2) = 0 + 0i = 0.

Associativity of Scalar Multiplication

The grouping of scalar multiplication does not affect the result.

c(dz1)=(cd)z1c(dz_1) = (cd)z_1

Distributivity of Scalar over Scalar Addition

A scalar can be distributed over the addition of scalars.

(c+d)z1=cz1+dz1(c + d)z_1 = cz_1 + dz_1

Distributivity of Scalar over Complex Addition

A scalar can be distributed over the addition of complex numbers.

c(z1+z2)=cz1+cz2c(z_1 + z_2) = cz_1 + cz_2

Scalar Multiplicative Identity

Multiplying a complex number by the scalar 1 does not change the complex number.

1z1=z11 z_1 = z_1

Multiplication by Zero Scalar

Multiplying a complex number by the scalar 0 results in the complex number zero.

0z1=00 z_1 = 0

Using the Operation Properties

These properties can be used to simplify or prove expressions involving complex numbers.

Example of Using Properties

Show that for any complex number zz, 4z+(4)z=04z + (-4)z = 0 holds.

Solution:

We can use the distributivity of scalar over scalar addition (property f) and the multiplication by zero scalar property (property i).

4z+(4)z=(4+(4))z(Distributive Property)4z + (-4)z = (4 + (-4))z \quad \text{(Distributive Property)}
=(0)z(Scalar addition)= (0)z \quad \text{(Scalar addition)}
=0(Multiplication by Zero Scalar Property)= 0 \quad \text{(Multiplication by Zero Scalar Property)}

Thus, it is proven that 4z+(4)z=04z + (-4)z = 0.

Exercise

Using the properties above, prove that 3z12(2z)=2z3z - \frac{1}{2}(2z) = 2z for any complex number zz.

Answer Key

3z12(2z)=3z+(12)(2z)(Definition of subtraction)3z - \frac{1}{2}(2z) = 3z + (-\frac{1}{2})(2z) \quad \text{(Definition of subtraction)}
=3z+((12)×2)z(Associativity of Scalar Multiplication)= 3z + ((-\frac{1}{2}) \times 2)z \quad \text{(Associativity of Scalar Multiplication)}
=3z+(1)z(Scalar multiplication)= 3z + (-1)z \quad \text{(Scalar multiplication)}
=(3+(1))z(Distributive Property)= (3 + (-1))z \quad \text{(Distributive Property)}
=(2)z(Scalar addition)= (2)z \quad \text{(Scalar addition)}
=2z= 2z

Thus, it is proven that 3z12(2z)=2z3z - \frac{1}{2}(2z) = 2z.