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Complex Number

Scalar Multiplication of Complex Numbers

What is Scalar Multiplication?

Scalar multiplication involves multiplying a complex number by a real number (a scalar).

Visualization of Scalar Multiplication
Notice how the vector z=1+2iz = 1+2i changes when multiplied by the scalar c=2c=2 and c=0.5c=-0.5.

From the visualization above, we can see:

  • Multiplying zz by a scalar c>1c > 1 (like 2) will stretch the vector zz in the same direction.
  • Multiplying zz by a scalar 0<c<10 < c < 1 will shrink the vector zz in the same direction.
  • Multiplying zz by a scalar c<0c < 0 (like -0.5) will reverse the direction of the vector zz (by 180 degrees) and change its length according to the value of c|c|.

Mathematical Definition

If z=x+iyz = x + iy is a complex number and cc is a scalar (a real number), then their scalar multiplication is:

cz=c(x+iy)=(cx)+i(cy)cz = c(x + iy) = (cx) + i(cy)

This means we simply multiply the scalar cc by the real part (xx) and the imaginary part (yy) separately.

Calculation Examples

If z=3+4iz = -3 + 4i and c=3c = 3, then:

cz=3(3+4i)=3(3)+i(3×4)=9+12icz = 3(-3 + 4i) = 3(-3) + i(3 \times 4) = -9 + 12i

If z=5iz = 5 - i and c=2c = -2, then:

cz=2(5i)=2(5)+i(2×1)=10+2icz = -2(5 - i) = -2(5) + i(-2 \times -1) = -10 + 2i

Visualization Examples

Let's look at a few more examples to clarify the effect of scalar multiplication.

Positive Scalar (> 1)

Multiplication by Scalar c=1.5c = 1.5
Vector z=2+iz = -2 + i is stretched in the same direction when multiplied by c=1.5c = 1.5, becoming 1.5z=3+1.5i1.5z = -3 + 1.5i.

Positive Scalar (0 < c < 1)

Multiplication by Scalar c=0.75c = 0.75
Vector z=32iz = 3 - 2i is shrunk in the same direction when multiplied by c=0.75c = 0.75, becoming 0.75z=2.251.5i0.75z = 2.25 - 1.5i.

Negative Scalar (c = -1)

Multiplication by -1 yields the additive inverse (negative) of the complex number.

Multiplication by Scalar c=1c = -1 (Additive Inverse)
Vector z=13iz = -1 - 3i reverses direction (180°) when multiplied by c=1c = -1, becoming z=1+3i-z = 1 + 3i.