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Complex Number

Addition of Complex Numbers

Addition of Two Complex Numbers

How do you add two complex numbers?

Suppose we have two complex numbers:

z1=x1+iy1z_1 = x_1 + iy_1
z2=x2+iy2z_2 = x_2 + iy_2

To add them (z1+z2z_1 + z_2), simply add the real parts together and the imaginary parts together.

z1+z2=(x1+x2)+i(y1+y2)z_1 + z_2 = (x_1 + x_2) + i(y_1 + y_2)

Addition Example

Let z1=2+3iz_1 = 2 + 3i and z2=1iz_2 = 1 - i.

  • The real part of z1z_1 is 2, the real part of z2z_2 is 1.
  • The imaginary part of z1z_1 is 3, the imaginary part of z2z_2 is -1.

Then their sum is:

z1+z2=(2+1)+i(3+(1))=3+i(2)=3+2iz_1 + z_2 = (2 + 1) + i(3 + (-1)) = 3 + i(2) = 3 + 2i

Visualization of Addition

Using the parallelogram rule, the addition of complex numbers can be viewed geometrically on the complex plane. If we represent z1z_1 and z2z_2 as vectors (arrows) from the origin (0,0), then their sum, z1+z2z_1 + z_2, is the diagonal vector of the parallelogram formed by z1z_1 and z2z_2.

Geometric Addition of Complex Numbers
Visualization of the sum z1=2+3iz_1 = 2+3i and z2=1iz_2 = 1-i using the parallelogram rule.

Besides addition, other operations work similarly:

Scalar Multiplication

Multiplying a complex number z=x+iyz = x + iy by a real number (scalar) cc is straightforward. Just multiply cc into both the real and imaginary parts.

cz=c(x+iy)=cx+i(cy)cz = c(x + iy) = cx + i(cy)

Geometrically, this scales the vector zz by a factor of cc. If cc is negative, the vector's direction is reversed.

Negative of a Complex Number

The negative of z=x+iyz = x + iy is z-z. This is the same as scalar multiplication by c=1c = -1.

z=(x+iy)=x+i(y)=xiy-z = -(x + iy) = -x + i(-y) = -x - iy

Geometrically, z-z is a vector with the same length as zz but pointing in the opposite direction (180 degrees rotation).

Subtraction of Two Complex Numbers

Subtracting z2z_2 from z1z_1 (z1z2z_1 - z_2) is the same as adding z1z_1 to the negative of z2z_2 (z1+(z2)z_1 + (-z_2)).

z1z2=z1+(z2)=(x1+(x2))+i(y1+(y2))=(x1x2)+i(y1y2)z_1 - z_2 = z_1 + (-z_2) = (x_1 + (-x_2)) + i(y_1 + (-y_2)) = (x_1 - x_2) + i(y_1 - y_2)

So, subtract the real parts and subtract the imaginary parts.

Geometrically, z1z2z_1 - z_2 is the vector from the tip of z2z_2 to the tip of z1z_1.

Example of Combined Operations

Suppose we have:

z1=2+12iz_1 = 2 + \frac{1}{2}i
z2=3+2iz_2 = -3 + \sqrt{2}i

Let's calculate some operations:

  1. 2z12z_1 (Scalar Multiplication):

    2z1=2(2+12i)=2(2)+i(2×12)=4+i2z_1 = 2(2 + \frac{1}{2}i) = 2(2) + i(2 \times \frac{1}{2}) = 4 + i
  2. z1+3z2z_1 + 3z_2 (Addition and Scalar Multiplication):

    z1+3z2=(2+12i)+3(3+2i)z_1 + 3z_2 = (2 + \frac{1}{2}i) + 3(-3 + \sqrt{2}i)
    =(2+12i)+(3(3)+i(32))= (2 + \frac{1}{2}i) + (3(-3) + i(3\sqrt{2}))
    =(2+12i)+(9+32i)= (2 + \frac{1}{2}i) + (-9 + 3\sqrt{2}i)
    =(29)+i(12+32)= (2 - 9) + i(\frac{1}{2} + 3\sqrt{2})
    =7+i(12+32)= -7 + i(\frac{1}{2} + 3\sqrt{2})
  3. 2z1z22z_1 - z_2 (Subtraction and Scalar Multiplication):

    2z1z2=(4+i)(3+2i)2z_1 - z_2 = (4 + i) - (-3 + \sqrt{2}i)
    =(4(3))+i(12)= (4 - (-3)) + i(1 - \sqrt{2})
    =(4+3)+i(12)= (4 + 3) + i(1 - \sqrt{2})
    =7+i(12)= 7 + i(1 - \sqrt{2})

Exercise

If z1=1+2iz_1 = 1 + 2i and z2=3iz_2 = 3 - i. Determine:

  1. z1+z2z_1 + z_2
  2. z1z2z_1 - z_2
  3. If z3=z1+z2z_3 = z_1 + z_2, draw z1z_1, z2z_2, and z3z_3 on the complex plane.

Answer Key

  1. z1+z2=(1+3)+i(2+(1))=4+iz_1 + z_2 = (1+3) + i(2+(-1)) = 4 + i
  2. z1z2=(13)+i(2(1))=2+i(3)=2+3iz_1 - z_2 = (1-3) + i(2-(-1)) = -2 + i(3) = -2 + 3i
  3. Visualization of z1z_1, z2z_2, and z3=z1+z2z_3 = z_1 + z_2 on the complex plane using the parallelogram rule:

    Addition of Complex Numbers
    Visualization of z1z_1, z2z_2, and z3=z1+z2z_3 = z_1 + z_2 on the complex plane using the parallelogram rule.