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Exponents and Logarithms

Exponential Growth

Definition of Exponential Growth Function

Exponential growth is a type of growth where the rate of change is proportional to its quantity. In this growth, the value increases more rapidly over time.

The exponential growth function is written as:

f(x)=axf(x) = a^x where a>1a > 1

Where:

  • aa is the base (growth constant)
  • xx is the variable (time)

Examples of Exponential Growth

Exponential growth is often found in real life, such as the growth of bacteria that divide into two at regular time intervals.

Bacterial Growth

A researcher observes bacterial growth on a host with an initial condition of 30 bacteria. These bacteria divide into two every 30 minutes.

If xx is the growth phase of bacteria every 30 minutes, then:

Phase (30 minutes)012345
Number of bacteria3060120240480960

It can be observed that:

  • For x=0x = 0, the number of bacteria = 30
  • For x=1x = 1, the number of bacteria = 60
  • For x=2x = 2, the number of bacteria = 120 = 22302^2 \cdot 30
  • For x=3x = 3, the number of bacteria = 240 = 23302^3 \cdot 30
  • For x=4x = 4, the number of bacteria = 480 = 24302^4 \cdot 30

From this pattern, bacterial growth can be modeled with an exponential function:

f(x)=30(2x)f(x) = 30 \cdot (2^x)

Visualization of Exponential Growth Graph

The graph of the function f(x)=30(2x)f(x) = 30 \cdot (2^x) shows growth that gets faster as the value of xx increases. A characteristic feature of exponential growth graphs is their increasingly steep curve.

Bacterial Growth
Growth of bacteria that divide into two every 30 minutes.

Calculating the Number of Bacteria at a Specific Time

If we want to calculate the number of bacteria at the 5th hour, we need to know that the 5th hour occurs at phase 10 (because each phase is 30 minutes):

f(10)=30(210)=301024=30,720f(10) = 30 \cdot (2^{10}) = 30 \cdot 1024 = 30,720

So, at the 5th hour, there are 30,720 bacteria.

Variations in Initial Value

Exponential growth can have different initial values. In general, if the initial value is P0P_0, then the exponential growth function becomes:

f(x)=P0(ax)f(x) = P_0 \cdot (a^x)

For example:

  • If the initial number of bacteria is 50, then f(x)=50(2x)f(x) = 50 \cdot (2^x)
  • If the initial number of bacteria is 100, then f(x)=100(2x)f(x) = 100 \cdot (2^x)
  • If the initial number of bacteria is 200, then f(x)=200(2x)f(x) = 200 \cdot (2^x)

Determining the Initial Value

Sometimes we need to determine the initial value x0x_0 of an exponential growth if we know its value at a certain time.

Example case:

Suppose we know that the number of bacteria at phase 2 is 8,000 and the bacteria divide into two at each time interval. What is the initial number of bacteria?

We can use the equation x2=a2x0x_2 = a^2 \cdot x_0 with a=2a = 2:

x2=a2x0x_2 = a^2 \cdot x_0
8000=22x08000 = 2^2 \cdot x_0
8000=4x08000 = 4 \cdot x_0
80004=x0\frac{8000}{4} = x_0
x0=2000x_0 = 2000

So, the initial number of bacteria is 2,000 bacteria.

Calculating Long-Term Growth

To calculate the number of bacteria after a longer time, we still use the same model. For example, to calculate the number of bacteria after 10 hours:

x10=a10x0x_{10} = a^{10} \cdot x_0

Substitute the values a=2a = 2 and x0=2,000x_0 = 2,000:

x10=2102,000x_{10} = 2^{10} \cdot 2,000
x10=1,0242,000x_{10} = 1,024 \cdot 2,000
x10=2,048,000x_{10} = 2,048,000

So, the number of bacteria after 10 hours is 2,048,000 bacteria.

Exercises

  1. E.coli bacteria cause diarrhea in humans. A researcher observed the growth of 50 of these bacteria on a piece of food and found that these bacteria divide into 2 every quarter of an hour.

    a. Draw a table and graph showing the growth of these bacteria from phase 0 to phase 5.

    b. Model the function that describes the growth of E.coli bacteria every quarter of an hour.

    c. Predict how many bacteria will be present after the first 3 and 4 hours.

  2. In 2015, positive HIV-AIDS cases totaled about 36 million people. This number increased by an average of 2% each year from 2010 to 2015. If the increase in positive HIV cases in subsequent years is predicted to increase exponentially at 2% each year, how many cases will occur in 2020?

Answer Key

  1. E.coli bacteria with an initial count of 50 bacteria that divide into two every 15 minutes.

    a. Bacterial Growth:

    Phase (15 minutes)012345
    Number of bacteria501002004008001,600
    Bacterial Growth
    Growth of bacteria that divide into two every 15 minutes.

    b. The E.coli bacterial growth function can be modeled as:

    f(x)=50(2x)f(x) = 50 \cdot (2^x)

    c. After the first 3 hours means phase 12 (bacteria divide every 15 minutes):

    f(12)=50(212)f(12) = 50 \cdot (2^{12})
    f(12)=504,096f(12) = 50 \cdot 4,096
    f(12)=204,800f(12) = 204,800

    After the first 4 hours means phase 16 (bacteria divide every 15 minutes):

    f(16)=50(216)f(16) = 50 \cdot (2^{16})
    f(16)=5065,536f(16) = 50 \cdot 65,536
    f(16)=3,276,800f(16) = 3,276,800
  2. HIV-AIDS cases:

    The number of cases in 2015 was 36,000,000 people with a 2% annual increase.

    Mathematical model:

    f(x)=36,000,000(1+0.02)xf(x) = 36,000,000 \cdot (1 + 0.02)^x

    To calculate cases in 2020 (5 years after 2015):

    f(5)=36,000,000(1.02)5f(5) = 36,000,000 \cdot (1.02)^5
    f(5)=36,000,0001.1040808f(5) = 36,000,000 \cdot 1.1040808
    f(5)=39,746,908f(5) = 39,746,908

    Therefore, the predicted number of HIV-AIDS cases in 2020 is approximately 39,746,908 people.

Other Applications of Exponential Growth

Exponential growth is also found in other contexts such as:

  • Compound interest in investments
  • Population growth of living organisms
  • Radioactive decay (negative growth)
  • Spread of infectious diseases

Exponential growth is very important in various fields such as biology, finance, and physics because it describes many real-world phenomena.